Matematika Sekolah Dasar Soal nya ada di foto

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Soal nya ada di foto

No ngasal !!
50 poin !!

1A.

» Volume Kerucut

= ⅓ × π × r² × tinggi

= ⅓ × 3,14 × 5² × 12

= ⅓ × 3,14 × 25 × 12

= 3,14 × 25 × 4

= 3,14 × 100

= 314 Cm³.

» Volume Tabung

= πr²tinggi

= 3,14 × 5² × 12

= 3,14 × 25 × 12

= 3,14 × 300

= 942 Cm³.

» Volume ½ Bola

= ½(4/3πr³)

= ½ × ( 4/3 × 3,14 × 5³ )

= ½ × ( 4/3 × 392,5 )

= ½ × ( 523,33 )

= 261,67 Cm³

» Volume Gabungan

= 314 + 942 + 261,67

= 1256 + 261,67

= 1.517,67 Cm³.

1B.

» Volume Limas Atas

= ⅓ × Luas Alas × Tinggi

= ⅓ × ( 12 × 12 ) × 10

= ⅓ × 144 × 10

= 48 × 10

= 480 Cm³

» Volume Kubus

= S³

= 12 × 12 × 12

= 144 × 12

= 1.728 Cm³

» Volume Limas Bawah

= ⅓ × Luas Alas × Tinggi

= ⅓ × ( 12 × 12 ) × 12

= ⅓ × 144 × 12

= 48 × 12

= 576 Cm³.

» Volume Gabungan

= 480 + 1728 + 576

= 480 + 2304

= 2.784 Cm³

1C.

» Volume Balok

= Panjang × Lebar × Tinggi

= 20 × 10 × 8

= 20 × 80

= 1.600 Cm³.

» Volume ½ Tabung

= ½ ( π r² t )

= ½ × ( 3,14 × 5² × 20 )

= ½ × ( 3,14 × 25 × 20 )

= ½ × ( 3,14 × 500 )

= ½ × 1570

= 785 Cm³.

» Volume Gabungan

= 1600 + 785

= 2.385 Cm³.

⃢~ Opung~⃠⃫⃟⃤᳗᳐

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